3(2x+1)(-x+3)-(2x+5)^2=(-(-3(x+5))+10x^2)

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Solution for 3(2x+1)(-x+3)-(2x+5)^2=(-(-3(x+5))+10x^2) equation: 



3(2x+1)(-x+3)-(2x+5)^2=(-(-3(x+5))+10x^2)

We move all terms to the left:

3(2x+1)(-x+3)-(2x+5)^2-((-(-3(x+5))+10x^2))=0

We add all the numbers together, and all the variables

-((-(-3(x+5))+10x^2))+3(2x+1)(-1x+3)-(2x+5)^2=0

We multiply parentheses ..

-((-(-3(x+5))+10x^2))+3(-2x^2+6x-1x+3)-(2x+5)^2=0



We calculate terms in parentheses: -((-(-3(x+5))+10x^2)), so:

(-(-3(x+5))+10x^2)



We calculate terms in parentheses: +(-(-3(x+5))+10x^2), so:

-(-3(x+5))+10x^2

determiningTheFunctionDomain
10x^2-(-3(x+5))



We calculate terms in parentheses: -(-3(x+5)), so:

-3(x+5)

We multiply parentheses

-3x-15

Back to the equation:

-(-3x-15)



We get rid of parentheses

10x^2+3x+15

Back to the equation:

+(10x^2+3x+15)



We get rid of parentheses

10x^2+3x+15

Back to the equation:

-(10x^2+3x+15)



We multiply parentheses

-6x^2+18x-3x-(10x^2+3x+15)-(2x+5)^2+9=0

We get rid of parentheses

-6x^2-10x^2+18x-3x-3x-(2x+5)^2-15+9=0

We add all the numbers together, and all the variables

-16x^2+12x-(2x+5)^2-6=0

We move all terms containing x to the left, all other terms to the right

-16x^2+12x-(2x+5)^2=6

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